Ôn tập chương III
Hướng dẫn giải Bài 98 (Trang 105 SGK Toán 9 Hình học, Tập 2)
<p>Cho đường tr&ograve;n (O) v&agrave; một điểm A cố định tr&ecirc;n đường tr&ograve;n. T&igrave;m quỹ t&iacute;ch c&aacute;c trung điểm M của d&acirc;y AB khi điểm B di động tr&ecirc;n đường tr&ograve;n đ&oacute;.</p> <p><strong>Giải :</strong></p> <p><em>Phần thuận: </em>Giả sử M l&agrave; trung điểm của d&acirc;y AB. Ta c&oacute;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>O</mi><mi>M</mi><mo>&#8869;</mo><mi>A</mi><mi>B</mi></math> (định l&iacute;).<img class="wscnph" 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width="138" height="146" /></p> <p>Khi B di động tr&ecirc;n (O), điểm M lu&ocirc;n nh&igrave;n OA cố định dưới g&oacute;c vu&ocirc;ng, vậy M thuộc đường tr&ograve;n đường k&iacute;nh OA.</p> <p><em>Phần đảo:&nbsp;</em>Lấy điểm M' bất kig tr&ecirc;n đường tr&ograve;n đường k&iacute;nh OA.</p> <p>Nối M' với A, đường thẳng M'A cắt đường tr&ograve;n (O) tại B'. Nối M' với O ta c&oacute;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mover><mrow><mi>A</mi><mi>M</mi><mo>'</mo><mi>O</mi></mrow><mo>^</mo></mover><mo>=</mo><mn>90</mn><mo>&#176;</mo></math> hay&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>O</mi><mi>M</mi><mo>'</mo><mo>&#8869;</mo><mi>A</mi><mi>B</mi><mo>'</mo></math> suy ra M' l&agrave; trung điểm của AB'.</p> <p><em>Kết luận:&nbsp;</em>Tập hợp c&aacute;c trung điểm của d&acirc;y AB l&agrave; đường tr&ograve;n đường k&iacute;nh OA.</p>
Hướng dẫn Giải Bài 98 (Trang 105, SGK Toán Hình học 9, Tập 2)
GV: GV colearn
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Hướng dẫn Giải Bài 98 (Trang 105, SGK Toán Hình học 9, Tập 2)
GV: GV colearn