Bài 3: Diện Tích Tam Giác
Hướng dẫn giải Bài 22 (Trang 123 SGK Toán Hình học 8, Tập 1)
<p>Đề b&agrave;i<br />Cho tam gi&aacute;c ABC. H&atilde;y chỉ ra một số vị tr&iacute; của điểm M nằm trong tam gi&aacute;c đ&oacute; sao cho:<br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>&#8290;</mo><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>B</mi></mrow></msub><mo>+</mo><msub><mi>S</mi><mrow><mi>B</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>&#8290;</mo></math><br />Lời giải chi tiết</p> <p><img src="https://img.loigiaihay.com/picture/2018/0716/b23-trang-123-sgk-toan-8-t-1-c2.jpg" /></p> <p>Kẻ đường cao BH, MK.<br />Theo giả thiết, M l&agrave; điểm nằm trong tam gi&aacute;c ABC sao cho:<br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>B</mi></mrow></msub><mo>+</mo><msub><mi>S</mi><mrow><mi>B</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub></mstyle></math> (1)<br />Ta lại c&oacute;: <math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>B</mi></mrow></msub><mo>+</mo><msub><mi>S</mi><mrow><mi>B</mi><mo>&#8290;</mo><mi>M</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>+</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub></mstyle></math><br />Thay (1) v&agrave;o (2) ta được: <math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>+</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub></mstyle></math><br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mrow><mo>&#8658;</mo><mn>2</mn></mrow><mo>.</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub></mstyle></math><br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mo>&#8658;</mo><msub><mi>S</mi><mrow><mi>M</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub><mo>=</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mo>&#8290;</mo><msub><mi>S</mi><mrow><mi>A</mi><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>C</mi></mrow></msub></mstyle></math><br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mo>&#8658;</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mi>M</mi><mi>K</mi><mo>.</mo><mi>A</mi><mi>C</mi><mo>=</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mrow><mo>(</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mi>B</mi><mi>H</mi><mo>.</mo><mi>A</mi><mi>C</mi><mo>)</mo></mrow></mstyle></math><br /><math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mo>&#8658;</mo><mi>M</mi><mo>&#8290;</mo><mi>K</mi><mo>=</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>H</mi></mstyle></math><br />Do đ&oacute;, M nằm tr&ecirc;n đường thẳng thuộc nửa mặt phẳng bờ AC chứa B sao cho khoảng c&aacute;ch từ M đến AC bằng <math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mfrac><mn>1</mn><mn>2</mn></mfrac></mstyle></math> đường cao BH.<br />Vậy điểm M nằm trong tam gi&aacute;c ABC v&agrave; nằm tr&ecirc;n đường trung b&igrave;nh ứng với cạnh AC của <math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="false"><mi mathvariant="normal">&#9651;</mi><mo>&#8290;</mo><mi>A</mi><mo>&#8290;</mo><mi>B</mi><mo>&#8290;</mo><mi>C</mi></mstyle></math></p>
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