Câu hỏi trắc nghiệm chương I
Hướng dẫn giải Bài 7 (Trang 28 SGK Toán Hình học 12)
<p>Cho h&igrave;nh ch&oacute;p S.ABCD. Gọi A', B', C', D' theo thứ tự l&agrave; trung điểm của SA, SB, SC, SD. Tỉ số thể t&iacute;ch của hai</p> <p>khối ch&oacute;p S.A'B'C'D' v&agrave; S.ABCD bằng:</p> <p>(A)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>2</mn></mfrac></math> ;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (B)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>4</mn></mfrac></math> ;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (C)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>8</mn></mfrac></math> ;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(D)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>16</mn></mfrac></math>.</p> <p><strong>Giải</strong></p> <p><img class="wscnph" src="https://static.colearn.vn:8413/v1.0/upload/library/22022022/hinh-38-JnUXrT.png" /></p> <p><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>B</mi><mo>'</mo><mi>C</mi><mo>'</mo></mrow></msub><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>B</mi><mi>C</mi></mrow></msub></mfrac><mo>=</mo><mfrac><mrow><mi>S</mi><mi>A</mi><mo>'</mo></mrow><mrow><mi>S</mi><mi>A</mi></mrow></mfrac><mo>.</mo><mfrac><mrow><mi>S</mi><mi>B</mi><mo>'</mo></mrow><mrow><mi>S</mi><mi>B</mi></mrow></mfrac><mo>.</mo><mfrac><mrow><mi>S</mi><mi>C</mi><mo>'</mo></mrow><mrow><mi>S</mi><mi>C</mi></mrow></mfrac><mo>=</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mo>.</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mo>.</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac><mspace linebreak="newline"/><mo>&#8658;</mo><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>B</mi><mo>'</mo><mi>C</mi><mo>'</mo></mrow></msub><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>B</mi><mi>C</mi></mrow></msub><mo>&#160;</mo><mo>&#160;</mo><mo>(</mo><mn>1</mn><mo>)</mo></math></p> <p>Tương tự:&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>C</mi><mo>'</mo><mi>D</mi><mo>'</mo></mrow></msub><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>C</mi><mi>D</mi></mrow></msub><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>(</mo><mn>2</mn><mo>)</mo></math></p> <p>Lấy (1) cộng (2) ta được:&nbsp;</p> <p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>B</mi><mo>'</mo><mi>C</mi><mo>'</mo><mi>D</mi><mo>'</mo></mrow></msub><mo>=</mo><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>B</mi><mo>'</mo><mi>C</mi><mo>'</mo></mrow></msub><mo>+</mo><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>C</mi><mo>'</mo><mi>D</mi><mo>'</mo></mrow></msub><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac><mo>(</mo><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>B</mi><mi>C</mi></mrow></msub><mo>+</mo><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>C</mi><mi>D</mi></mrow></msub><mo>)</mo><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mi>B</mi><mi>C</mi><mi>D</mi></mrow></msub></math></p> <p>Vậy&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><msub><mi>V</mi><mrow><mi>S</mi><mo>.</mo><mi>A</mi><mo>'</mo><mi>B</mi><mo>'</mo><mi>C</mi><mo>'</mo><mi>D</mi><mo>'</mo></mrow></msub><mi>V</mi></mfrac><mo>=</mo><mfrac><mn>1</mn><mn>8</mn></mfrac></math>. Chọn (C)</p>
Hướng dẫn Giải Bài 7 (trang 28, SGK Toán 12, Hình học)
GV: GV colearn
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Hướng dẫn Giải Bài 7 (trang 28, SGK Toán 12, Hình học)
GV: GV colearn