Bài 15: Ý nghĩa là cách tính biến thiên Enthalpy phản ứng hóa học
Hướng dẫn giải Mở đầu (Trang 82 SGK Hóa 10, Bộ Cánh diều)
<p><strong>Mở đầu (Trang 82 SGK H&oacute;a 10, Bộ C&aacute;nh diều):</strong></p> <p>Cho hai phản ứng đốt ch&aacute;y:</p> <p>(1):&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">C</mi><mo>(</mo><mi mathvariant="normal">s</mi><mo>)</mo><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><msub><mi mathvariant="normal">O</mi><mn>2</mn></msub><mo>(</mo><mi mathvariant="normal">g</mi><mo>)</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><msub><mi>CO</mi><mn>2</mn></msub><mo>(</mo><mi mathvariant="normal">g</mi><mo>)</mo><mo>&#160;</mo><mo>&#160;</mo><msub><mo>&#8710;</mo><mi mathvariant="normal">r</mi></msub><mo>,</mo><msubsup><mi mathvariant="normal">H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>393</mn><mo>,</mo><mn>5</mn><mo>&#160;</mo><mi>kJ</mi></math></p> <p>(2):&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mi>Al</mi><mo>(</mo><mi mathvariant="normal">s</mi><mo>)</mo><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mfrac><mn>3</mn><mn>2</mn></mfrac><msub><mi mathvariant="normal">O</mi><mn>2</mn></msub><mo>(</mo><mi mathvariant="normal">g</mi><mo>)</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><msub><mi>Al</mi><mn>2</mn></msub><msub><mi mathvariant="normal">O</mi><mn>3</mn></msub><mo>(</mo><mi mathvariant="normal">s</mi><mo>)</mo><mo>&#160;</mo><mo>&#160;</mo><msub><mo>&#8710;</mo><mi mathvariant="normal">r</mi></msub><mo>,</mo><msubsup><mi mathvariant="normal">H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>1675</mn><mo>,</mo><mn>7</mn><mo>&#160;</mo><mi>kJ</mi></math></p> <p>Với c&ugrave;ng một khối lượng C v&agrave; Al, chất n&agrave;o khi đốt ch&aacute;y tỏa ra nhiều nhiệt hơn?</p> <p>&nbsp;</p> <p><strong><span style="text-decoration: underline;"><em>Hướng dẫn giải:</em></span></strong></p> <p>Giả sử đốt ch&aacute;y 1 gam C v&agrave; 1 gam Al:</p> <p>+) 1 gam C c&oacute; 1/12 mol</p> <p>1 mol C:&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mo>&#8710;</mo><mi>r</mi></msub><mo>,</mo><msubsup><mi>H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>393</mn><mo>,</mo><mn>5</mn><mo>&#160;</mo><mo>&#8658;</mo><mo>&#160;</mo><mfrac><mn>1</mn><mn>12</mn></mfrac><mi>m</mi><mi>o</mi><mi>l</mi><mo>&#160;</mo><mi>C</mi><mo>&#160;</mo><mi>c</mi><mi>&#243;</mi><mo>&#160;</mo><msub><mo>&#8710;</mo><mi>r</mi></msub><mo>,</mo><msubsup><mi>H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>32</mn><mo>,</mo><mn>79</mn><mo>&#160;</mo><mi>k</mi><mi>J</mi><mo>.</mo></math></p> <p>+) 1 gam Al c&oacute; 1/27 mol</p> <p>Với 2 mol Al ta c&oacute;&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mo>&#8710;</mo><mi mathvariant="normal">r</mi></msub><mo>,</mo><msubsup><mi mathvariant="normal">H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>1675</mn><mo>,</mo><mn>7</mn><mo>&#160;</mo><mi>kJ</mi><mo>&#160;</mo><mo>&#8658;</mo><mo>&#160;</mo><mfrac><mn>1</mn><mn>27</mn></mfrac><mi>mol</mi><mo>&#160;</mo><mi>Al</mi><mo>&#160;</mo><mi>c&#243;</mi><mo>&#160;</mo><msub><mo>&#8710;</mo><mi mathvariant="normal">r</mi></msub><mo>,</mo><msubsup><mi mathvariant="normal">H</mi><mn>298</mn><mn>0</mn></msubsup><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>31</mn><mo>,</mo><mn>03</mn><mo>&#160;</mo><mi>kJ</mi></math></p> <p>=&gt; Với c&ugrave;ng một khối lượng C v&agrave; Al, C khi đốt ch&aacute;y tỏa ra nhiều nhiệt hơn.</p>
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