Làm tính chia:

$$\begin{gathered} a) (-2x^5+3x^2-4x^3) : 2x^2; \\ b) (x^3-2x^{3}y+3x{y}^2) : (-\frac{1}{2}x); \\ c) (3x^2{y}^2+6x^2{y}^3-12xy) : 3xy; \end{gathered}$$

Giải:

$$\begin{gathered} a) (-2x^5+3x^2-4x^3) : 2x^2 \\ =\left(-\frac{2}{2}\right)x^{5-2}+\frac{3}{2}{x}^{2-2}+\left(-\frac{4}{2}\right)x^{3-2} \\ =- x^3 + \frac{3}{2} – 2x \end{gathered}$$

$$\begin{gathered} b) (x^3-2x^{3}y+3x{y}^2) : (-\frac{1}{2}x) \\ =(x^3 :-\frac{1}{2}x) + (-2x^{2}y :-\frac{1}{2}x) + (3x{y}^2 :-\frac{1}{2}x) \\ = -2x^2 + 4xy – 6y^2 \end{gathered}$$

$$\begin{gathered} c) (3x^2{y}^2+6x^2{y}^3-12xy) : 3xy \\ = (3x^2{y}^2 : 3xy) + (6x^2{y}^2 : 3xy) + (-12xy : 3xy) \\ = xy + 2x{y}^2 – 4 \end{gathered}$$