Bài 1: Số phức
Hướng dẫn giải Bài 6 (Trang 134 SGK Toán Giải tích 12)
<p><strong>B&agrave;i 6 (Trang 134 SGK To&aacute;n Giải t&iacute;ch 12):</strong></p> <p>T&igrave;m&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mover><mi>z</mi><mo>&#175;</mo></mover></math> , biết:</p> <p>a) <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">z</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>1</mn><mo>&#160;</mo><mo>-</mo><mo>&#160;</mo><mi mathvariant="normal">i</mi><msqrt><mn>2</mn></msqrt></math>;</p> <p>b) <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">z</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><msqrt><mn>2</mn></msqrt><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi mathvariant="normal">i</mi><msqrt><mn>3</mn></msqrt></math>;</p> <p>c) <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">z</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>5</mn></math>;</p> <p>d) <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">z</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>7</mn><mi mathvariant="normal">i</mi></math>.</p> <p><strong><em>Hướng dẫn giải:</em></strong></p> <p>a)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose notation="top"><mi mathvariant="normal">z</mi></menclose><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>1</mn><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mo>&#160;</mo><mi mathvariant="normal">i</mi><msqrt><mn>2</mn></msqrt></math></p> <p>b)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose notation="top"><mi mathvariant="normal">z</mi></menclose><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><msqrt><mn>2</mn></msqrt><mo>&#160;</mo><mo>-</mo><mo>&#160;</mo><mi mathvariant="normal">i</mi><msqrt><mn>3</mn></msqrt></math></p> <p>c)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose notation="top"><mi mathvariant="normal">z</mi></menclose><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>5</mn></math></p> <p>d)&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose notation="top"><mi mathvariant="normal">z</mi></menclose><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>-</mo><mn>7</mn><mi mathvariant="normal">i</mi></math></p>
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