Bài 4: Khối lượng riêng. Áp suất chất lỏng
Hướng dẫn giải Câu hỏi 3 (Trang 62 SGK Vật lý 10, Bộ Cánh diều)
<p><strong>&nbsp;</strong>Từ định nghĩa đơn vị lực, h&atilde;y chứng tỏ: 1 Pa = 1 N/m<sub>2</sub></p> <p><strong>Lời giải:</strong></p> <p>Lực F c&oacute; đơn vị l&agrave; N</p> <p>Diện t&iacute;ch bị &eacute;p c&oacute; đơn vị l&agrave; m<sup>2</sup>.</p> <p>Ta c&oacute; c&ocirc;ng thức t&iacute;nh &aacute;p suất:&nbsp;<span id="MathJax-Element-1-Frame" class="mjx-chtml MathJax_CHTML" style="box-sizing: border-box; display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 21.78px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;" tabindex="0" role="presentation" data-mathml="&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mi&gt;p&lt;/mi&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mfrac&gt;&lt;mi&gt;F&lt;/mi&gt;&lt;mi&gt;S&lt;/mi&gt;&lt;/mfrac&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mfrac&gt;&lt;mrow&gt;&lt;mn&gt;1&lt;/mn&gt;&lt;mi&gt;N&lt;/mi&gt;&lt;/mrow&gt;&lt;mrow&gt;&lt;mn&gt;1&lt;/mn&gt;&lt;msup&gt;&lt;mi&gt;m&lt;/mi&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;/msup&gt;&lt;/mrow&gt;&lt;/mfrac&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mn&gt;1&lt;/mn&gt;&lt;mi&gt;P&lt;/mi&gt;&lt;mi&gt;a&lt;/mi&gt;&lt;/math&gt;"><span id="MJXc-Node-1" class="mjx-math" aria-hidden="true"><span id="MJXc-Node-2" class="mjx-mrow"><span id="MJXc-Node-3" class="mjx-mi"></span></span></span><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p</mi><mo>=</mo><mfrac><mi>F</mi><mi>S</mi></mfrac><mo>=</mo><mfrac><mrow><mn>1</mn><mi>N</mi></mrow><mrow><mn>1</mn><msup><mi>m</mi><mn>2</mn></msup></mrow></mfrac><mo>=</mo><mn>1</mn><mi>P</mi><mi>a</mi></math><math xmlns="http://www.w3.org/1998/Math/MathML"><mi></mi></math></span>&nbsp;(đpcm)</p> <p>N&ecirc;n 1Pa = 1N/1m<sup>2</sup>.</p>
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