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Bài 2.27 trang 46 Toán 8 tập 1
<p><strong>B&agrave;i 2.27 trang 46 To&aacute;n 8 Tập 1:&nbsp;</strong>Ph&acirc;n t&iacute;ch c&aacute;c đa thức sau th&agrave;nh nh&acirc;n tử:</p> <p>a) x<sup>3</sup>&nbsp;+ y<sup>3</sup>&nbsp;+ x + y;</p> <p>b) x<sup>3</sup>&nbsp;&ndash; y<sup>3</sup>&nbsp;+ x &ndash; y;</p> <p>c) (x &ndash; y)<sup>3</sup>&nbsp;+ (x + y)<sup>3</sup>;</p> <p>d) x<sup>3</sup>&nbsp;&ndash; 3x<sup>2</sup>y + 3xy<sup>2</sup>&nbsp;&ndash; y<sup>3</sup>&nbsp;+ y<sup>2</sup>&nbsp;&ndash; x<sup>2</sup>.</p> <p><strong>Lời giải:</strong></p> <p>a) x<sup>3</sup>&nbsp;+ y<sup>3</sup>&nbsp;+ x + y = (x<sup>3</sup>&nbsp;+ y<sup>3</sup>) + (x + y)</p> <p>= (x + y)(x<sup>2</sup>&nbsp;&ndash; xy + y<sup>2</sup>) + (x + y)</p> <p>= (x + y)(x<sup>2</sup>&nbsp;&ndash; xy + y<sup>2</sup>&nbsp;+ 1);</p> <p>b) x<sup>3</sup>&nbsp;&ndash; y<sup>3</sup>&nbsp;+ x &ndash; y = (x<sup>3</sup>&nbsp;&ndash; y<sup>3</sup>) + (x &ndash; y)</p> <p>= (x &ndash; y)(x<sup>2</sup>&nbsp;+ xy + y<sup>2</sup>) + (x &ndash; y)</p> <p>= (x &ndash; y)(x<sup>2</sup>&nbsp;+ xy + y<sup>2</sup>&nbsp;+ 1);</p> <p>c) (x &ndash; y)<sup>3</sup>&nbsp;+ (x + y)<sup>3</sup></p> <p>= [(x &ndash; y) + (x + y)] [(x &ndash; y)<sup>2</sup>&nbsp;&ndash; (x &ndash; y)(x + y) + (x + y)<sup>2</sup>]</p> <p>= (x &ndash; y + x + y) [(x &ndash; y)<sup>2</sup>&nbsp;&ndash; (x<sup>2</sup>&nbsp;&ndash; y<sup>2</sup>) + (x + y)<sup>2</sup>]</p> <p>= 2x(x<sup>2</sup>&nbsp;&ndash; 2xy + y<sup>2</sup>&nbsp;&ndash; x<sup>2</sup>&nbsp;+ y<sup>2</sup>&nbsp;+ x<sup>2</sup>&nbsp;+ 2xy + y<sup>2</sup>)</p> <p>= 2x(x<sup>2</sup>&nbsp;+ 3y<sup>2</sup>);</p> <p>d) x<sup>3</sup>&nbsp;&ndash; 3x<sup>2</sup>y + 3xy<sup>2</sup>&nbsp;&ndash; y<sup>3</sup>&nbsp;+ y<sup>2</sup>&nbsp;&ndash; x<sup>2</sup></p> <p>= (x<sup>3</sup>&nbsp;&ndash; 3x<sup>2</sup>y + 3xy<sup>2</sup>&nbsp;&ndash; y<sup>3</sup>) &ndash; (x<sup>2&nbsp;</sup>&ndash; y<sup>2</sup>)</p> <p>= (x &ndash; y)<sup>3</sup>&nbsp;&ndash; (x &ndash; y)(x + y)</p> <p>= (x &ndash; y) [(x &ndash; y)<sup>2&nbsp;</sup>&ndash; (x + y)]</p> <p>= (x &ndash; y) (x<sup>2</sup>&nbsp;&ndash; 2xy + y<sup>2&nbsp;</sup>&ndash; x &ndash; y).</p>
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