Bài 53: Protein
Hướng dẫn Giải Bài 4 (Trang 160, SGK Hóa học 9)
<p>a) So s&aacute;nh sự giống nhau v&agrave; kh&aacute;c nhau về th&agrave;nh phần, cấu tạo ph&acirc;n tử của axit aminoaxetic (H<sub>2</sub>N-CH<sub>2</sub>-COOH) với axit axetic.</p> <p>b) Hai ph&acirc;n tử axit aminoaxetic kết hợp với nhau bằng c&aacute;ch t&aacute;ch -OH của nh&oacute;m -COOH v&agrave; -H của nh&oacute;m -NH<sub>2</sub>. H&atilde;y viết phương tr&igrave;nh h&oacute;a học</p> <h3 style="text-align: center;">Giải</h3> <p>a)</p> <p>Về th&agrave;nh phần nguy&ecirc;n tố:</p> <ul> <li>Giống nhau: Đều chứa cacbon, hiđro, oxi.</li> <li>Kh&aacute;c nhau: Trong ph&acirc;n tử axit aminoaxetic ngo&agrave;i ba nguy&ecirc;n tố tr&ecirc;n c&ograve;n c&oacute; nguy&ecirc;n tố nitơ.</li> </ul> <p>Về cấu tạo ph&acirc;n tử:</p> <ul> <li>Giống nhau: Đều c&oacute; nh&oacute;m -COOH</li> <li>Kh&aacute;c nhau: Axit aminoaxetic c&ograve;n c&oacute; nh&oacute;m -NH<sub>2</sub></li> </ul> <p>b) Phương tr&igrave;nh h&oacute;a học của phản ứng giữa 2 aminoaxit:</p> <p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>H</mi><mn>2</mn></msub><mi>N</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>2</mn></msub><mo>-</mo><munder><mi>C</mi><mrow><mo>|</mo><mo>|</mo></mrow></munder><mo>-</mo><mi>O</mi><mi>H</mi><mo>+</mo><mn>2</mn><msub><mi>H</mi><mn>2</mn></msub><mi>N</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>2</mn></msub><mo>-</mo><munder><mi>C</mi><mrow><mo>|</mo><mo>|</mo></mrow></munder><mo>-</mo><mi>O</mi><mi>H</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mspace linebreak="newline"/><mover><mo>&#8594;</mo><mrow><mi>X</mi><mi>&#250;</mi><mi>c</mi><mo>&#160;</mo><mi>t</mi><mi>&#225;</mi><mi>c</mi></mrow></mover><msub><mi>H</mi><mn>2</mn></msub><mi>N</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>2</mn></msub><mo>-</mo><munder><mi>C</mi><mrow><mo>|</mo><mo>|</mo></mrow></munder><mo>-</mo><mi>N</mi><mi>H</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>2</mn></msub><mo>-</mo><munder><mrow><mi>C</mi><mo>-</mo><mi>O</mi><mi>H</mi><mo>+</mo><msub><mi>H</mi><mn>2</mn></msub><mi>O</mi></mrow><mrow><mo>|</mo><mo>|</mo></mrow></munder><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mo>&#160;</mo><mspace linebreak="newline"/></math></p> <p>&nbsp;</p> <p>&nbsp;</p>
Hướng dẫn giải bài tập 4 (Trang 160 SGK Hóa 9)
GV: GV colearn
Xem lời giải bài tập khác cùng bài
Video hướng dẫn giải bài tập
Hướng dẫn giải bài tập 4 (Trang 160 SGK Hóa 9)
GV: GV colearn