Bài 28: Luyện tập: Tính chất của kim loại kiềm, kim loại kiềm thổ và hợp chất của chúng
Hướng dẫn giải Bài 2 (Trang 132 SGK Hóa học 12)
<p>Sục 6,72 l&iacute;t kh&iacute; CO<sub>2</sub> (đktc) v&agrave;o dung dịch c&oacute; chứa 0,25 mol Ca(OH)<sub>2</sub>. Khối lượng kết tủa thu được l&agrave;</p> <p>A. 10 gam.&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; B. 15 gam.</p> <p>C. 20 gam.&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; D. 25 gam.</p> <p><strong>Giải</strong></p> <p><em>Chọn C</em>. Số mol CO<sub>2</sub> :&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">n</mi><mo>=</mo><mfrac><mrow><mn>6</mn><mo>,</mo><mn>72</mn></mrow><mrow><mn>22</mn><mo>,</mo><mn>4</mn></mrow></mfrac><mo>=</mo><mn>0</mn><mo>,</mo><mn>3</mn><mo>&#160;</mo><mi>mol</mi></math>; s&ocirc; mol Ca(OH)<sub>2</sub> : n = 0,25 mol</p> <p>Ta c&oacute;:&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn><mo>&#60;</mo><mi mathvariant="normal">k</mi><mo>=</mo><mfrac><msub><mi mathvariant="normal">n</mi><msup><mi>OH</mi><mo>-</mo></msup></msub><msub><mi mathvariant="normal">n</mi><msub><mi>CO</mi><mn>2</mn></msub></msub></mfrac><mo>=</mo><mfrac><mrow><mn>0</mn><mo>,</mo><mn>25</mn><mo>.</mo><mn>2</mn></mrow><mrow><mn>0</mn><mo>,</mo><mn>3</mn></mrow></mfrac><mo>=</mo><mn>1</mn><mo>,</mo><mn>67</mn><mo>&#160;</mo><mo>&#60;</mo><mo>&#160;</mo><mn>2</mn><mo>&#160;</mo><mo>&#8658;</mo></math>Tạo hai muối.</p> <p>Đặt số mol của CO<sub>2</sub> tham gia phản ứng lần lượt l&agrave; x mol v&agrave; y mol.</p> <p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CO</mi><mn>2</mn></msub><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi>Ca</mi><msub><mrow><mo>(</mo><mi>OH</mi><mo>)</mo></mrow><mn>2</mn></msub><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><msub><mi>CaCO</mi><mn>3</mn></msub><mo>&#8595;</mo><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mi mathvariant="normal">x</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi mathvariant="normal">x</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi mathvariant="normal">x</mi><mspace linebreak="newline"/><mn>2</mn><msub><mi>CO</mi><mn>2</mn></msub><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi>Ca</mi><msub><mrow><mo>(</mo><mi>OH</mi><mo>)</mo></mrow><mn>2</mn></msub><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><mi>Ca</mi><msub><mrow><mo>(</mo><msub><mi>HCO</mi><mn>3</mn></msub><mo>)</mo></mrow><mn>2</mn></msub><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi mathvariant="normal">y</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>5</mn><mi mathvariant="normal">y</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#8594;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>5</mn><mi mathvariant="normal">y</mi></math></p> <p>Ta c&oacute;:&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced open="{" close=""><mtable columnalign="left"><mtr><mtd><mi mathvariant="normal">x</mi><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi mathvariant="normal">y</mi><mo>&#160;</mo><mo>=</mo><mn>0</mn><mo>,</mo><mn>3</mn></mtd></mtr><mtr><mtd><mi mathvariant="normal">x</mi><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>5</mn><mi mathvariant="normal">y</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>25</mn></mtd></mtr></mtable></mfenced><mo>&#8660;</mo><mfenced open="{" close=""><mtable columnalign="left"><mtr><mtd><mi mathvariant="normal">x</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>2</mn></mtd></mtr><mtr><mtd><mi mathvariant="normal">y</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mn>0</mn><mo>,</mo><mn>1</mn></mtd></mtr></mtable></mfenced></math></p> <p>Khối lượng kết tủa thu được: m = 0,2.100 = 20 (g).</p>
Hướng dẫn Giải Bài 2 (Trang 132, SGK Hóa học 12)
GV: GV colearn
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Hướng dẫn Giải Bài 2 (Trang 132, SGK Hóa học 12)
GV: GV colearn