Bài 46: Luyện tập: Anđehit – xeton – axit cacboxylic
Hướng dẫn giải Bài 6 (Trang 213 SGK Hóa học 11)
<p>Viết phương tr&igrave;nh h&oacute;a học của c&aacute;c phản ứng ho&agrave;n th&agrave;nh d&atilde;y chuyển h&oacute;a sau:</p> <p><img src="https://vietjack.com/giai-hoa-lop-11/images/bai-6-trang-213-sgk-hoa-11.PNG" alt="Giải b&agrave;i tập H&oacute;a học 11 | Để học tốt h&oacute;a học 11" /></p> <p><span style="text-decoration: underline;">Hướng dẫn</span></p> <p>(1) :&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>C</mi><msub><mi>H</mi><mn>2</mn></msub><mo>&#160;</mo><mo>=</mo><mi>C</mi><mi>H</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>+</mo><msub><mi>H</mi><mn>2</mn></msub><mi>O</mi><mo>&#160;</mo><mo>&#160;</mo><mover><mo>&#8594;</mo><msup><mi>H</mi><mo>+</mo></msup></mover><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>-</mo><mi>C</mi><mi>H</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>|</mo><mo>&#160;</mo><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mi>H</mi></math></p> <p>(2) :&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>-</mo><mi>C</mi><mi>H</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi>C</mi><mi>u</mi><mi>O</mi><mo>&#160;</mo><mo>&#160;</mo><mover><mrow><mo>&#8594;</mo><mo>&#160;</mo></mrow><msup><mi>t</mi><mi>O</mi></msup></mover><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>-</mo><mi>C</mi><mi>H</mi><mo>-</mo><mi>C</mi><msub><mi>H</mi><mn>3</mn></msub><mo>&#160;</mo><mo>+</mo><mo>&#160;</mo><mi>C</mi><mi>u</mi><mo>&#160;</mo><mo>-</mo><mo>&#160;</mo><msub><mi>H</mi><mn>2</mn></msub><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>|</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>|</mo><mo>|</mo><mspace linebreak="newline"/><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi><mi>H</mi><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mo>&#160;</mo><mi>O</mi></math></p> <p>(3) : CH<sub>2</sub>=CH-CH<sub>3 </sub>+ Cl<sub>2</sub>&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mover><mo>&#8594;</mo><mrow><mi>A</mi><mi>s</mi><mo>,</mo><mo>&#160;</mo><msup><mi>t</mi><mi>O</mi></msup></mrow></mover></math> CH<sub>2</sub>=CH-CH<sub>2</sub>OH&nbsp; + NaBr</p> <p>(4) :&nbsp; CH<sub>2</sub>=CH-CH<sub>2</sub>Cl&nbsp; + NaOH&nbsp; &nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mover><mo>&#8594;</mo><msup><mi>t</mi><mi>O</mi></msup></mover></math>CH<sub>2</sub>=CH-CH<sub>2</sub>OH&nbsp; + NaBr</p> <p>(5) : CH<sub>2</sub>=CH-CH<sub>2</sub>OH&nbsp; + CuO&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mover><mo>&#8594;</mo><msup><mi>t</mi><mi>O</mi></msup></mover></math>CH<sub>2</sub>=CH-CHO +Cu + H<sub>2</sub>O</p>
Hướng dẫn giải bài tập 6 (Trang 212 SGK Hóa 11)
GV: GV colearn
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Hướng dẫn giải bài tập 6 (Trang 212 SGK Hóa 11)
GV: GV colearn