Bài 2: Sự biến dạng
Hướng dẫn giải Luyện tập 1 (Trang 115 SGK Vật lý 10, Bộ Cánh diều)
<p>Dưới t&aacute;c dụng của một lực k&eacute;o 2,5 N một l&ograve; xo d&agrave;i th&ecirc;m 25 mm. Độ cứng của l&ograve; xo l&agrave; bao nhi&ecirc;u?</p> <p><strong>Lời giải:</strong></p> <p>Lực k&eacute;o t&aacute;c dụng l&ecirc;n l&ograve; xo bằng với lực đ&agrave;n hồi.</p> <p>Suy ra: &nbsp;<span id="MJXc-Node-3" class="mjx-mi"></span><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>F</mi><mo>=</mo><mi>k</mi><mfenced open="|" close="|"><mrow><mo>∆</mo><mi>l</mi></mrow></mfenced><mo>&rArr;</mo><mi>k</mi><mo>=</mo><mfrac><mi>F</mi><mrow><mo>∆</mo><mi>l</mi></mrow></mfrac><mo>=</mo><mfrac><mrow><mn>2</mn><mo>,</mo><mn>5</mn></mrow><mrow><mn>0</mn><mo>,</mo><mn>025</mn></mrow></mfrac><mo>=</mo><mn>100</mn><mi>N</mi><mo>/</mo><mi>m</mi></math><span id="MJXc-Node-39" class="mjx-mi"></span><span id="MathJax-Element-1-Frame" class="mjx-chtml MathJax_CHTML" style="box-sizing: border-box; display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: 400; font-size: 21.78px; letter-spacing: normal; overflow-wrap: normal; word-spacing: 0px; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: #000000; font-family: 'Open Sans', Arial, sans-serif; font-variant-ligatures: normal; font-variant-caps: normal; orphans: 2; widows: 2; -webkit-text-stroke-width: 0px; background-color: #ffffff; text-decoration-thickness: initial; text-decoration-style: initial; text-decoration-color: initial; position: relative;" tabindex="0" role="presentation" data-mathml="&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mi&gt;F&lt;/mi&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mi&gt;k&lt;/mi&gt;&lt;mfenced open=&quot;|&quot; close=&quot;|&quot;&gt;&lt;mrow&gt;&lt;mi&gt;&amp;#x394;&lt;/mi&gt;&lt;mi mathvariant=&quot;script&quot;&gt;l&lt;/mi&gt;&lt;/mrow&gt;&lt;/mfenced&gt;&lt;mo&gt;&amp;#x21D2;&lt;/mo&gt;&lt;mi&gt;k&lt;/mi&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mfrac&gt;&lt;mi&gt;F&lt;/mi&gt;&lt;mfenced open=&quot;|&quot; close=&quot;|&quot;&gt;&lt;mrow&gt;&lt;mi&gt;&amp;#x394;&lt;/mi&gt;&lt;mi mathvariant=&quot;script&quot;&gt;l&lt;/mi&gt;&lt;/mrow&gt;&lt;/mfenced&gt;&lt;/mfrac&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mfrac&gt;&lt;mrow&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;mo&gt;,&lt;/mo&gt;&lt;mn&gt;5&lt;/mn&gt;&lt;/mrow&gt;&lt;mrow&gt;&lt;mn&gt;0&lt;/mn&gt;&lt;mo&gt;,&lt;/mo&gt;&lt;mn&gt;025&lt;/mn&gt;&lt;/mrow&gt;&lt;/mfrac&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mn&gt;100&lt;/mn&gt;&lt;mtext&gt;&amp;#x2009;&lt;/mtext&gt;&lt;mi&gt;N&lt;/mi&gt;&lt;mo&gt;/&lt;/mo&gt;&lt;mi&gt;m&lt;/mi&gt;&lt;/math&gt;"><span id="MJXc-Node-1" class="mjx-math" aria-hidden="true"><span id="MJXc-Node-2" class="mjx-mrow"><span id="MJXc-Node-3" class="mjx-mi"></span></span></span></span></p>
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